First, we need to find which number when substituted into the equation will give the answer zero. \(f(1) = {(1)^3} + 4{(1)^2} + (1) - 6 = 0\) Therefore \((x - 1)\)is a factor. Factorise the quadratic ...

We show that the binary expansions of algebraic numbers do not form secure pseudorandom sequences; given sufficiently many initial bits of an algebraic number, its minimal polynomial can be ...

In this paper we consider cubic polynomial systems of the form: ẋ = y + P(x, y), ẏ = -x + Q(x, y), where P and Q are polynomials of degree 3 without linear part ...