Solution: det (A) = −5, and for n×n matrix adj (A) has determinant (det A)^ (n−1). Here n = 3, so det (B) = (−5)^ (2) = 25.
My algorithm for calculating matrix determinants isn't working as it should, so I'm turning to Ars for some maths help.<BR><BR><BR>So...<BR>I'm trying to find the ...
Some results have been hidden because they may be inaccessible to you
Show inaccessible results
Feedback